What 5 consecutive numbers add up to 100?

Let n be the first number. Then the next four numbers will be n+1, n+2, n+3, and n+4. Add the five numbers together and set them equal to 100: (n) + (n+1) + (n+2) + (n+3) +(n+4) = 100. Add together the five terms on the left to get 5n + 10 and let that equal 100: 5n +10 = 100.

What is the sum of five consecutive even numbers?

The five numbers are 900, 902, 904, 906 and 908. these 5 consecutive even numbers are . 900 , 902 , 904 , 906 , and , 908 . and the sum of these numbers is 4520 .

What is the average of 5 consecutive even numbers?

Detailed solution: As these are consecutive numbers, B = A + 2, C = A + 4, D = A + 6, E = A + 8. ∴ B × E = 50 × 56 = 2800.

What are two consecutive odd numbers?

If x is any odd number, then x and x + 2 are consecutive odd numbers. E.g. 7 and 9 are consecutive odd numbers, as are 31 and 33.

What is the sum of first odd number and consecutive numbers?

Sum of first odd number = 1. The square root of 1, √1 = 1, so, only one digit was added. Sum of consecutive two odd numbers = 1 + 3 = 4.

What is the smallest of the 5 consecutive odd numbers?

If the sum of 5 odd consecutive odd numbers is 345, then the middle number = 345/5 = 69. So the 5 numbers will be: 65, 67, 69, 71 and 73. The smallest of the 5 numbers is thus 65. Let the smallest integer be x. Since it is a sum of five consecutive odd integers the other integers are x+2,x+4, x+6 and x+8.

What are the 5 consecutive odd integers that add up to 345?

If the sum of five consecutive odd integers is 345, the average of those five integers is 345/5=69. The five integers will be clustered around the average and since all five are consecutive odd integers clustered around 69, that suggests 65,67,69,71, and 73, which do indeed add up to 345.

Which is the first consecutive odd integer 2k-1?

2k-1 2k − 1 which is also one of the general forms of an odd integer. 2k-1 2k − 1 be the first consecutive odd integer. As discussed in Method 1, odd integers are also