How long will it take for the ball to hit the ground formula?

We will assume v₀ = 0 . Choose how long the object is falling. In this example, we will use the time of 8 seconds. Calculate the final free fall speed (just before hitting the ground) with the formula v = v₀ + gt = 0 + 9.80665 * 8 = 78.45 m/s .

What is the quadratic equation when the ball hits the ground?

When the ball hits the ground, the height is 0. Substitute 0 for h h . This equation is difficult to solve by factoring or by completing the square, so solve it by applying the Quadratic Formula, x=−b±√b2−4ac2a x = − b ± b 2 − 4 a c 2 a . In this case, the variable is t t rather than x x .

How long will it take the ball to reach its maximum height?

You don’t even need to find out the height, it’s just a matter of measuring the time it takes for gravity to reduce the speed to 0. In mathematical terms, it can be considered as: If and , then . That means it takes 3.058 s for the ball to reach its maximum height.

How long in seconds does it take the rocket to reach the maximum height?

The first term ( -4.9(t-4)^2 ) can never be positive, so the maximum height of 80 meters is achieved when t = 4. So the rocket will reach its maximum height after 4 seconds.

How do you find the height of a ball in feet?

The height in feet of the ball can be modeled by the equation h = -16t 2 + 20t + 6 where t is the time in seconds, the ball is. 0. 3. 51858. 5. +68. A ball is thrown into the air. The height in feet of the ball can be modeled by the equation h = -16t 2 + 20t + 6 where t is the time in seconds, the ball is in the air.

What is the height h above the ground of a baseball?

Question 133135: The height h (in feet) above the ground of a baseball depends upon the time t (in seconds) it has been in flight. Cameron takes a mighty swing, but hits a bloop sinlge whose height is described approximately by the equation h=80t-16t^2.

How high does a juggler throw the ball?

 A juggler throws a ball in the air, releasing it 5 feet above the ground with an initial velocity of 15 feet per second.  She catches the ball with her other hand when the ball returns to 5 feet above the ground.  If the equation,  y = –16×2 + 15x, gives the path of the ball from hand to hand, find how high she throws the ball.

How do you find the height of a projectile in time?

feet of a vertically launched projectile in terms of time: h(t)=-16t2+vt+s. h=height (feet) t=time in motion (seconds) s=initial height (feet) v=initial velocity (feet per sec) Notice that the function is quadratic, which when graphed will be parabolic.