What is the value of m and n if m39048458n is divisible by 8 and 11?

A number is divisible by 8 , if the number formed by the last three digits is divisible by 8. Again a number is divisible by 11, if the difference between the sum of digits at even places and sum of digits at the odd places is either 0 or divisible by 11. It cannot be zero hence, M + 5 = 11 ⇒ M=6.

What is the value of m and n?

Therefore, the value of m and n is 2 and 0, respectively.

Which one of the following numbers is exactly divisible by 11?

Consider the following numbers which are divisible by 11, using the test of divisibility by 11: (i) 154, (ii) 814, (iii) 957, (iv) 1023, (v) 1122, (vi) 1749, (vii) 53856, (viii) 592845, (ix) 5048593, (x) 98521258. -1 is divisible by 11. Hence, 154 is divisible by 11.

Which one of the following number is completely divisible by 99?

Description for Correct answer: A number divisible by 99 must be divisible by 9 as well as 11. Clearly, 114345 is divisible by both 9 and 11 i.e. 99.

How many 3 digit numbers are there which are divisible by 6?

150
The value of n = 6. Thus, the number of 3-digit numbers divisible by 6 is 150.

How many divisors does 7200 have *?

54 factors
Factors of 7200 are integers that can be divided evenly into 7200. It has total 54 factors of which 7200 is the biggest factor and the prime factors of 7200 are 2, 3, 5. The Prime Factorization of 7200 is 25 × 32 × 52.

For what value of k do the equations 3x 8 0 and 6x =- 16 represent coincident lines?

Answer: For k = 2, the two equations 3x-y+8=0 and 6x-ky=-16 represent coincident lines.

What is the divisibility test of 11?

Here an easy way to test for divisibility by 11. Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11.

How do you find divisibility by 99?

For a number to be divisible by 99, the given number has to be divisible by 9 and 11, both of which are simple tests. Divisible by 9 test. If sum of digits is divisible by 9 then the number is divisible by 9.

Is a number divisible by 99 i The number is simultaneously divisible by 9 and 11 II a number formed by reversing the digits of the same number is divisible by 99?

99 = 9 * 11 => If the number is divisible by 9 and 11, then the number is divisible by 99. => We can answer the question using only statement I. According to statement II, if the number is reversed then the number is divisible by 9 and 11 => Divisible by 99.

Is m39048458 divisible by 8 and 11?

Well M39048458N is divisible by 8 and 11. For the number to be divisible 8, the last three digits should be divisible by 8. So N should be 4 for4584 is divisible by 8. So we have M390484584. Next the sum of the even digits must be the same as the sum of odd digits, or the difference should be 11, in order to be divisible by 11.

What is the sum of the even numbers in m390484584?

So we have M390484584. Next the sum of the even digits must be the same as the sum of odd digits, or the difference should be 11, in order to be divisible by 11. The sum of the numbers in the even position is = 3+0+8+5+4 = 20.

Which number is divisible by 8 when n = 4?

N=4, M= 6….. option 3. last three digits 58N is divisible by 8 when N = 4. If the digits at odd and even places of a given number are equal or differ by a number divisible by 11, then the given number is divisible by 11. Is this solution Helpfull?

Is 58N divisible by 8?

N can have just one value for 58N to be divible by 8. Incidently if the last three digits were 56N then there would be two possible solutions. If the number is divisible by 8 then it’s last three digits must be divisible by 8. Therefore, 58N must be divisible by 8.