How do you find the 6th term in AP?

a= 17. a6=? a6= -25. Therefore, the 6th term of the AP is -25.

What is the 6th term of the arithmetic?

Sum = 9a + 45d = 108. Or a + 5d = 12. Hence 6th term = 12. SUFFICIENT.

What is the 10th term AP 2 7 12?

Therefore, the 10th term of the given AP is 47.

What is the 12th of AP 2 7 12?

Common difference = d = b – a = c – b. Common difference = d = 7 – 2 = 12 – 7. Common difference = d = 5.

What is the 6th term at the end of AP 17 14 11?

Therefore, the sixth term from the end of the series is -25.

What is the 6th term of the arithmetic sequence I the sum of the 6th to the 12th term of the sequence is 77 II the sum of the 2nd to the 10th term of the sequence is 108?

We have to find the 6th term of an arithmetic sequence. The sum of the 6th to the 12th term is 77. Using the sum upto n terms formula we get 77 = 7/2(a6 + a12) where a6 is the 6th term and a12 is the 12th term. From this we can determine that a9 = 11.

Which term of the AP 12/17 2227 is 6 time the 26th term of the AP?

Answer: The required term is 163rd term.

How do you find the AP term?

The formula for the nth term of an AP is, Tn = a + (n – 1)d.

How do you find the tenth term?

1 Expert Answer to advance from 7th to 21st term of an arithmetic sequence one must add the constant difference 14 times. from 21 to 301 is advancement by 280, in total; thus d = 280/14 = 20. Tenth term is 21 + 3(20) = 81.

What is the 6th term in the geometric sequence Sequence 2 6 18?

⇒ =2×243=486.

What is the 10th term of AP 2 7 12 12?

Given AP 2, 7, 12, ………… We have to find 10th term So, n = 10 Also , a = 2 & d = 7 – 2 = 5 Putting these value in formula an = a + (n – 1)d a10 = 2 + (10 – 1) (5) a10 = 2 + 9 × 5 = 2 + 45 = 47 So, 10th term is 47

What is the sum of the first n terms of AP?

The sum of the first n terms of an AP is given by S = n/2 [2a + (n – 1) d] Where a is the first term, d is the common difference and n is the number of terms. (i) 2, 7, 12,… , to 10 terms. We know that sum up to n th term of AP is given by formula S n = n/2 [2a + (n – 1) d]

What is the value of the sixth term of an AP?

The sixth term of an A.P is equal to 2. The value of the common difference of the A.P which makes the product a1 a4 a5

What is the formula to find the nth term of an AP?

Formula Lists General Form of AP a, a + d, a + 2d, a + 3d, . . . The nth term of AP an = a + (n – 1) × d Sum of n terms in AP S = n/2 [2a + (n − 1) × d] Sum of all terms in a finite AP with the n/2 (a + l)