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Which has higher resistance 100w or 25W bulb?
ANSWER: 25W has the highest resistance.
Which among a 25W bulb and a 40w bulb has a higher resistance?
Power in Watt = Voltage^2 / Resistance. So 25 w bulb has higher resistance.
When a 25W 220v bulb and a 100w 220v bulb are connected in parallel then which bulb will glow brighter?
25W bulb will glow brighter. This is because P=I2R where I is the current flowing and R is the resistance of the appliance. When I is same, P∝R. The resistance of 25W bulb is more and therefore P is more.
Which has a higher resistance a 50 watt lamp bulb or 25 watt lamp bulb and how many times?
Resistance R = V2/P, where V is the potential difference and P is the power in Watts. So, the more the power, the lower will be the resistance and vice versa. Or, R2 = 2R1. Thus, 25 W bulb will have double the resistance as compared to 50 Watt bulb.
Should the resistance of a voltmeter be low or high give reason?
The resistance of a voltmeter should be high because voltmeter is always connected in parallel across a device. Reason – Negligible current passes through high resistance.
Which one has a higher resistance A 50W 220v or a 25W 220 V bulb and by how many times?
Under a constant (fixed) applied voltage (V), R2>R1, 25W bulb has higher resistance. Resistance of 25 W lamp bulb is twice the resistance of 50W lamp bulb.
Which has more resistance 100w bulb or 60w bulb?
A 60-watt bulb has a higher electrical resistance than a 100-watt bulb. Because power is inversely proportional to resistance, when the power is less, the resistance is high.
What happens if voltmeter has low resistance?
A voltmeter is always coonected in parallel across a device to measure the voltage across it. Now, if the voltmeter has low resistance, then the current will split and flow through the voltmeter also, thereby giving incorrect or undesired results across the device.
Which has high resistance voltmeter or ammeter?
Thus, out of galvanometer, voltmeter and ammeter, resistance of ammeter is lowest and resistance of voltmeter is highest. If the ammeter is connected in series, whole current flowing in the circuit flows through the ammeter with a very low resistance.
When a 40W bulb is connected in series to a 100W bulb which bulb glows more brightly justify your answer?
Now more current will flow in the bulb which has less resistance which is 100W bulb this time which means 100W bulb dissipate more power than 80W bulb (P=I2R) where current and resistance are directly proportional to the power. Hence, 100W bulb will glow brighter in a parallel circuit.