How do you calculate the velocity of the boat relative to the shore?

Figure 3.18 The velocity of the boat relative to the shore is vBS. It is the vector sum of the velocity vBW of the boat relative to the water and the velocity vWS of the water relative to the shore:vBS = vBW+vWS. The velocity of the boat relative to the shore is vBS.

What is the velocity of the boat relative to the earth?

5.4m/s
What is the velocity of the boat with respect to Earth? vBE=5.4m/s, θ=tan−1(3.04.5)=33.7°.

What is river boat problem?

To solve river boat problems, we need to understand two concepts: The velocity of a boat relative to the water (→vb/w v → b / w ) is equal to the difference in velocity of the boat relative to the ground (→vb v → b ) and velocity of water relative to the ground (→vw v → w ) i.e., →vb/w=→vb−→vw.

When a boat is moving in a river does the water Offer force of friction to its movement?

When a boat is moving in the river, does the water offer force of friction to its movement? Yes, the water opposes the movement of the boat.

How do you find the resultant velocity of a motorboat?

The resultant velocity of the motorboat can be determined in the same manner as was done for the plane. The resultant velocity of the boat is the vector sum of the boat velocity and the river velocity.

How does the river current affect the motion of the boat?

The river current influences the motion of the boat and carries it downstream. The motorboat may be moving with a velocity of 4 m/s directly across the river, yet the resultant velocity of the boat will be greater than 4 m/s and at an angle in the downstream direction.

How does velocity affect the time to cross the river?

The time to cross the river is dependent upon the velocity at which the boat crosses the river. It is only the component of motion directed across the river (i.e., the boat velocity) that affects the time to travel the distance directly across the river (80 m in this case).

How do you find the direction of the resultant velocity?

a. The resultant velocity can be found using the Pythagorean theorem. The resultant is the hypotenuse of a right triangle with sides of 5 m/s and 2.5 m/s. It is. SQRT [ (5 m/s) 2 + (2.5 m/s) 2] = 5.59 m/s. Its direction can be determined using a trigonometric function. Direction = 360 degrees – invtan[ (2.5 m/s) / (5 m/s) ] = 333.4 degrees