How do you find the defective ball from 8 ball?

How do you find the defective ball from 8 ball?

Now let’s analyse the three conditions to find the defective ball:

  1. Condition 1: If C1 is equal C2, then C3 has the defective ball. Now measure the weights of ball B7 and B8.
  2. Condition 2: If C1 < C2, then C1 has the defective ball.
  3. Condition 3: If C1 > C2, then C2 has the defective ball.

How much does a regulation pool ball weigh?

Billiard balls typically weight between five and one half to six ounces, or between 156 and 170 grams.

How do you get a heavy ball?

To figure out which one it is, weigh any two against each other — say, A versus B. If one or the other is heavier, then you’ve found your answer. If the scale balances, then you know the heavy ball is C.

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How many balls are all the same size and weight?

If they don’t weigh equal, take any two balls from heavier group and weigh them. If they weigh equal, the other ball is heavier. Originally Answered: You have eight balls all of the same size. 7 of them weigh the same, and one of them weighs slightly more.

How many balls are on each side of a scale?

Don’t answer three. Three is wrong. It’s the tempting answer — weigh all the balls, four on each side. Determine which side is heavier. Then take the heavier group of four and divide them again, two on one side of the scale, and two on the other.

How do you weigh an odd ball on a scale?

Weighing 2: Depending on the first weighing, take the group of three balls with the odd ball and put one ball on each side and keep the third ball off to the side. If the scale balances, the odd ball is the one left off to the side. Otherwise, the odd ball is the heavier (or lighter ball).

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How do you find the heavier ball?

Find the heavier ball. Answer: For convenience sake, let’s name the balls 1-8. First we weigh {1,2,3} on the left and {4,5,6} on the right. There are three scenarios which can arise from this. If the left side is heavier, then we know that one of 1, 2 or 3 is the heavier ball. Weigh {1} on the left and {2} on the right.