How do you find the equation of a straight line that passes through points?

How do you find the equation of a straight line that passes through points?

The straight line through two points will have an equation in the form y = m x + c . We can find the value of , the gradient of the line, by forming a right-angled triangle using the coordinates of the two points.

What will be the equation of the straight line whose passing through origin point and makes the angle 60 with the positive direction of x-axis?

Find the equation of a line which cuts off intercept 5 on the x-axis and makes an angle of 60^(@) with the positive direction of the x-axis. The given line passes through the point (5,0) and m=tan60∘=√3. So, the required equation is y-0x-5=√3⇔y=√3(x-5).

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What is the slope of a line if a line makes an angle of 30o with the positive x-axis and it also passes through X 1 and 2 − 3 Find the value of x?

Thus, the slope of the line is -√3.

What will be the equation of the line if the line makes a 45 degree angle with the x-axis?

The formula is m=tan() where m is the slope and theta is the angle. Plugging in 45 degrees into the above equation for theta yield m=tan(45) which is 1, so a line with an angle of 45 degrees has a slope of 1.

How do you write an equation for a straight line?

The general equation of a straight line is y = mx + c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis. The equation of a straight line with gradient m and intercept c on the y-axis is y = mx + c.

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What is the equation of the line whose x intercept is 2 and Y intercept is 3?

Slope = 2 and y – intercept = 3 , then the equation of line is y = mx + c .

What is the slope of line passing through origin?

If the line passes through the origin, then you know that (0,0) is on the line. If the line is perpendicular to y=2x+3 then we know the line has slope m=−0.5. This is the negative reciprocal of the slope.

How do you find the direction of a straight line?

Find the direction in which a straight line must be drawn through the point (–1, 2) so that its point of intersection with the line x + y = 4 may be at a distance of 3 units from this point. y = mx + m + 2 ……

What is the general equation of a straight line?

The general equation of straight line is as given below: ax + by + c = 0 { equation of straight line. Where x, y are variables and a,b, c are constants.

How do you find the slope of a straight line?

The relation between variables x, y satisfy all points on the curve. The general equation of straight line is as given below: ax + by + c = 0 { equation of straight line. Where x, y are variables and a,b, c are constants. ‘tan θ’ is called slope of straight line.

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How do you find the gradient of a straight line?

Therefore the gradient of a straight line is equal to the tangent of the angle formed between the line and the positive direction of the \\ (x\\)-axis. Gradient is undefined since there is no change in the \\ (x\\)-values (\\ (\\Delta x = 0\\)).