How do you solve equations with exponential expressions?

To solve an exponential equation, take the log of both sides, and solve for the variable. Ln(80) is the exact answer and x=4.38202663467 is an approximate answer because we have rounded the value of Ln(80).. Check: Check your answer in the original equation.

How do you multiply exponential equations?

In order to multiply two exponential expressions together, they must have the same base, and all you need to do is add the exponents. This works if the exponents are positive or negative, but only if the bases are the same. If the terms have different bases, there is not much that can be done to simplify.

How do you calculate exponential value on a calculator?

On most calculators, you enter the base, press the exponent key and enter the exponent. Here’s an example: Enter 10, press the exponent key, then press 5 and enter. (10^5=) The calculator should display the number 100,000, because that’s equal to 105.

What is x 3 = y if y = 0?

Defined as a real function, x = y 3 is the unique real number which satisfies x 3 = y. But, if y ≠ 0, this equation has three complex solutions which are three vectors in the complex plane making 120º angles between them.

How do I solve 3^(X-1) = 27 = 3^x 2?

1. Substitute 3^x = a (or any variable you want), then, rewrite the equation and solve further to get a = 27 = 3^x 2. Take 3^ (x-1) common to get the equation 3. Write 90 as a sum which suits the format of equation as .. I agree with Ashish Yogi, since this not at all a hard problem.

What is the minimum value of x^x for x=1/e?

The minimum value of x^x, for any positive real value of x, is around 0.6922, for x= 1/e. To verify that this is the minimum value of x^x, take This has no solution for any positive real value of x. The minimum value of x^x, for any positive real value of x, is around 0.6922, for x= 1/e.

What is the value of X when two curves cross?

The first starts at 3 when x=0, reaches 12 when x=1, and 50 when x=2. The second starts at 1 when x=0, 9 when x=1, and 81 when x=2. Therefore, somewhere between 1 and 2, the two curves crossed. There is an answer, and it’s somewhere between 1 and 2. With more accurate arithmetic you can narrow the interval down.