How does gravity decrease with an increase in depth?

As the depth increases the mass of the earth decreses. At the surface of the earth this value will be maximum because R will be max. When R becomes less ( i.e when depth increases) this value also decreases. Hence, acceleration due to gravity decreases with increase in depth.

How does value of G decrease with depth?

Why does the value of ‘g’ decrease as we go deep inside a mine (or the Earth)? Hint: The effective mass of the earth decreases as we go deep inside the earth. As the gravitational force of attraction depends on the mass of earth as well. As a result, the decrease in mass is more effective.

What is the effect of depth on gravity?

For an object placed at a height h, the acceleration due to gravity is less as compared to that placed on the surface. As depth increases, the value of acceleration due to gravity (g) falls. The value of g is more at poles and less at the equator.

What happens to the acceleration due to gravity as we go to a depth below the surface of the earth?

Acceleration due to gravity decreases linearly with increase in depth. Thus, acceleration due to gravity is maximum at the Earth’s surface and is zero at the center of the Earth and at infinite distance above the Earth’s surface.

At what depth is acceleration due to gravity g2?

Therefore, acceleration due to gravity will be g/2 at the depth of Re/2. Hope this helped you.

What will be the change in the value of g while going in depth?

The change in the value of g at a height h about the surface of the earth is the same as at a depth d below the surface of earth.

Why the value of g decreases as we go deep inside the earth?

The value of g REDUCES as we go deep inside the earth because the respective spherical mass of earth decreases, that is, the radius of earth decreases, which results in the decrease of mass of earth, as the density of the earth remains same throughout.

What is effect of altitude and depth of the earth on the value of g?

Acceleration due to gravity increases with depth and decreases with altitude.

How g varies with height and depth?

Variation of g with height is expressed by the formula g1 = g (1 – 2h/R). Variation of g with depth is expressed by the formula g2 = g (1 – d/R). Here g1 is the acceleration due to gravity at a height of h with respect to the earth’s surface.

How does g vary with depth and height?

as the distance increases,the g decreases and also when the distance decreases ,the g decreases as when we get inside the earth,the mass of the also decreases and the formula becomes Gm1m2r/R³ where r is the depth,R is radius of earth.

How does the acceleration due to gravity change for the same value of height and depth?

At an altitude ‘h’ g(h)=GM(R+h)2 because R+h is the distance from centre of earth to the given point at ‘h’. So accleration due to gravity decreases with height above the ground. Variation of ‘g’ with depth: When we go deep into the ground ‘g’ value decreases. So ‘g’ value decreases with depth below the ground.

Why does gravity decrease with increase in depth?

“The gravitational flux, through any closed surface, is proportional to the enclosed mass.”. So gravity decreases with increase in depth as the effective mass applying the gravitational force decreases as you go down.

How do you find acceleration due to gravity at different depths?

Variation of g with depth As depth h increases below the earth’s surface the value of acceleration due to gravity falls. This is expressed by the formula g2 = g (1 – h/R).

What is the relationship between gravity and mass?

“The gravitational flux, through any closed surface, is proportional to the enclosed mass.”. In integral form, So gravity decreases with increase in depth as the effective mass applying the gravitational force decreases as you go down.

What is the acceleration due to gravity at the earth’s surface?

As depth h increases below the earth’s surface the value of acceleration due to gravity falls. This is expressed by the formula g2 = g (1 – h/R). Here g2 is the acceleration due to gravity at depth h and R is the radius of the earth. So at a depth h below the earth’s surface, the value of g falls by this amount: gh/R