How many ways 2 boys and 1 girl can be selected from 3 boys and 2 girls?

120 ways. So total no of words = Answer to the problem = 4*6*120=2880 words. 2 boys can be selected in 5C2 ways. So the selection for photograph will happen in 5C2*3C1 =5*4*3/(1*2)=30 ways.

How many ways can a group of 3 boys and 2 girls be formed?

Hence, the total number of ways in which the group can be formed are 24 ways.

How many different ways are possible to arrange 2 girls and three boys on a bench of five so that at least 2 boys will seat next to each other?

2! options (3! for order of boys and 2! for girls), so we do indeed have 3×3! 2! =36 ways.

How many ways can you pick 3 boys out of 7?

Number of ways to choose 3 boys out of 7 = 7C3. Number of ways to choose 2 girls out of 4 = 4C2. Therefore, number of ways to choose the required groups = 7C3 * 4C2 = 35 * 6 = 210.

How many ways can 3 boys and 4 girls sit in a row of chairs where no two boys and no two girls should sit together?

=1202=60 ways. Now, from the fundamental principle of multiplication, we can say that the number of ways in which 4 girls and 3 boys be seated in a row so that no two boys are together will be equal to m×n=24×60=1440 ways. Thus, the required number of ways will be 1440 ways.

How many ways are there if two of the persons are not allowed to sit next to each other?

That can be done in 2⋅6! =1440 ways.

How many ways can a team of 3 boys and 3 girls be selected from 5 boys and 5 girls?

[ use the concept of ⁿCₐ =n!/a!( n-a)! ] = { 5 × 4/2} × { 4 × 3!/3!} = 40 ways .

How many units can be arranged with 2 girls and 3 boys?

2 Girls and 3 Boys shold be arranged in row such that 2 girls should sit together. Now you should consider 2 girls into one unit. So you are having 4 units. They can be arranged in 4! ways = 24. But both girls can interchange their places so answer is 24*2 = 48

How many combinations of 3 boys and 2 girls can be formed?

Possible combinations of 3 boys from 6 boys = 6!/ (3!) (3!) = 20. Possible combinations of 2 girls from 5 girls = 5!/ (3!) (2!) = 10. Possible combinations of 3 boys and 2 girls that can be formed from a group of 6 boys and 5 girls is thus = 10*20 = 200.

How many times can you order 3 boys in the lottery?

To figure out how many times, you need to count how many ways there are to order 3 boys (it was trivial with the 2 girls). It is quite simple, 3 ways to pick the first, 2 ways to pick the second, only one way to pick the last.

How many ways of choosing 3 boys from a group of 5?

There are 5 boys from whom to choose the first boy. Having chosen him, there are 4 boys left from whom to choose the second boy. And having chosen him, there are 3 boys left from whom to choose the third boy. So there are 5 x 4 x 3 = 60 ways of choosing 3 boys from a group of 5 boys.