How many ways can 4 boys and 3 girls be arranged?

How many ways can 4 boys and 3 girls be arranged?

Now, from the fundamental principle of multiplication, we can say that the number of ways in which 4 girls and 3 boys be seated in a row so that no two boys are together will be equal to m×n=24×60=1440 ways. Thus, the required number of ways will be 1440 ways.

How many ways can 4 boys and 3 girls stand in line if a the girls stand together?

Required number of ways=4! ×3! ×2! =288.

What is the number of ways that 4 boys?

The number of ways the four boys can be arranged in four places is 4! =4×3×2×1=24 .

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How many ways can 5 prizes be given away to 4 individuals if each one is eligible for all the prizes?

The answer says 1024, which I guess is coming from 45. So its like “4 students fit into each prize” + repeats allowed + 5 prizes =45=1024.

How many ways can the boys and girls sit in row?

According to the solution file provided by Toby Mak, they meant to ask in how many ways the boys and girls can sit in a row, with all girls sitting together and all boys sitting together. In this case we can have B B B G G G or G G G B B B, which again results in 2 ⋅ 3! ⋅ 3! = 72 possible arrangements.

How many ways can 3 girls be arranged to sit together?

Since a girl has to sit next to a girl only therefore all the girls would sit together G1,G2,G3,G4 or G2,G3,G1,G4 etc. Now these girls can be arranged in 4! = 24 ways. Now we have 3 boys who can be made to sit together in 3! = 6 ways.

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How many possible arrangements are there for the first boy?

There are 3 options for the first boy and girl, 2 for the second and 1 for the last, so the number of possible arrangements equals: Edit: the question is indeed not clear at all.

How many units to permute 3 single Boys to 4 girls?

$\\begingroup$@JeanFerreira Yes 3 single-boy units + 1 unit of 4 girls = 4 units to be permuted.$\\endgroup$ – Deepak Jun 15 ’14 at 15:56 $\\begingroup$As stated, the solution given is half what the correct answer should be.$\\endgroup$ – amWhy Jun 15 ’14 at 16:00 | Show 1more comment 4 Answers 4 ActiveOldestVotes