What is the average of 10 natural number?

What is the average of 10 natural number?

Thus, 5.5 is an average of first 10 natural numbers or positive integers.

How many natural numbers are there between 1 and 10?

The natural numbers between 1 and 10 are 2, 3, 4, 5, 6, 7, 8 and 9. That is 8 numbers when counted. Therefore there are 8 natural numbers between 1 and 10.

What is the range of first 10 whole numbers?

Answer: The first 10 whole numbers are 0,1,2,3,4,5,6,7,8,9. The range of first ten whole numbers is 9.

What is the average of square of the natural number from 1 to 10?

first 10 natural numbers. ∴ The average of squares of first 10 natural numbers is 38.5.

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How many natural numbers are there between 1 and 10 Brainly?

There are 8 natural numbers between 1 and 10.

How many natural numbers are there between 9 and 10?

R D Sharma – Mathematics 9 There are 18 Natural Numbers between the squares of 9 and 10.

What are the 10 natural numbers?

What are the first ten Natural Numbers? The first ten natural numbers are: 1,2,3,4,5,6,7,8,9, and 10.

How many whole numbers is 10?

8 whole numbers
There are total 8 whole numbers between 1 to 10.

What is the average of first 10 even numbers?

even numbers. 11 is an average of first 10 even numbers mentioned in the below table, by substituting the total sum and count of numbers in the formula. The corresponding formulas, chart, examples & workout may help students, teachers or professionals to learn, teach or practice the average of first n natural numbers calculation.

What is the average of first 10 natural numbers or positive integers?

The first 10 numbers. 1, 2, 3, . . . . , 9, 10. step 2 Find the sum of first 10 natural numbers. 1 + 2 + 3 + . . . . + 9 + 10 = 55. step 3 Divide the sum by 10. 55/10 = 5.5. Thus, 5.5 is an average of first 10 natural numbers or positive integers.

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What is the sum of the first n squares of 10?

The sum of squares of the first n natural numbers is: To get the average of the first n terms, you’d divide by n, so just drop the first term. Thus the average of the sums of the first n natural numbers is: For the specific case of n=10, that would be (11) (21)/6 = 38.5.

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