Table of Contents
What is the distance between two converging lenses?
Two converging lenses, with the focal length f 1 = 10 cm and f 2 = 15 cm are placed 40 cm apart, as shown on the figure. An object is placed 60 cm in front of the first lens as show in second figure.
What is the focal length of two lens system?
Two lens system – Image distance and magnification Home Problems and Answers Optics Two lens system – Image distance and magnification Two converging lenses, with the focal length f 1 = 10 cm and f 2 = 15 cm are placed 40 cm apart, as shown on the figure. An object is placed 60 cm in front of the first lens as show in second figure.
What is the radius of curvature of an equiconvex lens?
An equiconvex lens is made up of a material with refractive index 1.5 and it has a radius of curvature of 20 cm. What is the focal length? Solution: The radii of curvature of the two surfaces are equal i.e. R 1 = – R 2 = R. Refractive index =1.5 and R=20 cm. If the focal length is f, applying lens maker formula,
What is the formula for concave and convex lenses?
For a concave lens, R 1 is negative and R 2 is positive. The lens maker formula for concave lens is given by, 1 f = – (μ 1 μ 2 − 1) (1 R 1 + 1 R 2) For a convex lens, R 1 is positive and R 2 is negative.
What is the difference between image formation by concave and convex lenses?
The size of the image is much smaller than that of the object. When an object is placed at a finite distance from the lens, a virtual image is formed between the pole and the focus of the convex lens. The size of the image is larger than that of the object. Summary of Image Formation by Concave and Convex Lens
What happens when an object is placed at a finite distance?
When an object is placed at a finite distance from the lens, a virtual image is formed between the pole and the focus of the convex lens. The size of the image is larger than that of the object.
How do you find the image distance from the lens equation?
To determine the image distance, the lens equation can be used. Apply lens equation to first lens. di1 = 12 cm First image located 12 cm behind the first lens.