Table of Contents
What is the last digit of 5power2020?
Answer: the last digit of 5 to the power of 2020 is 25 because 5^6=78125 you will observe that any number will have 25 as the last two digits.
What is the last digit of 6¹00?
6
So, the last digit of 6^100 is 6.
What are the last 3 digits in the integer equal to 5 to the power of 2020?
Answer: As can be seen, after the 3rd power, the last three digits are 125 and 625 alternatively. 125 for odd powers, 625 for even powers. As 2020 is even, last three digits of 52020 should be 625.
How do you find the cyclicity of a number?
Digits 4 & 9: Both these numbers have a cyclicity of only two different digits as their unit’s digit. Let us take a look at how the powers of 4 operate: 41 = 4, 42 = 16, 43 = 64, and so on….Cyclicity Table.
| Number | Cyclicity | Power Cycle |
|---|---|---|
| 7 | 4 | 7, 9, 3, 1 |
| 8 | 4 | 8, 4, 2, 6 |
| 9 | 2 | 9, 1 |
| 10 | 1 | 0 |
What is the last digit of 6 N?
Step-by-step explanation: For any value of n, last digit of 6^n always ends with 6. Hope this helps you.
What is the last math number?
A googol is the large number 10100. In decimal notation, it is written as the digit 1 followed by one hundred zeroes: 10,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000.
What is the last digit of 3^2015?
When the remainder is 1 the last digit is 3. When the remainder is 2 the last digit is 9. When the remainder is 3 the last digit is 7. When the remainder is 0 the last digit is 1. Finally the last digit of 3^2015 is 7.
How do you find the last digit of a number?
To find last digit of a number, we use modulo operator \%. When modulo divided by 10 returns its last digit. Suppose if n = 1234. then last Digit = n \% 10 => 4. To finding first digit of a number is little expensive than last digit.
How to find last digit of a number using modulo?
To find last digit of a number, we use modulo operator \%. When modulo divided by 10 returns its last digit. Suppose if n = 1234 then last Digit = n \% 10 => 4
How do you find the last 2 digits of a power?
In general, the last digit of a power in base n n n is its remainder upon division by n n n. For decimal numbers, we compute m o d 10 \\bmod~{10} m o d 1 0 . Finding the last 2 digits of an integer amounts to computing it mod 100 , 100, 1 0 0 , and finding the last n {n} n digits amounts to computation m o d 1 0 n \\bmod~10^{n} m o d 1 0 n .