What is the maximum value of 2sinx COSX?

What is the maximum value of 2sinx COSX?

2sinx. cosx=(1/2)sin2x. Sin2x being a sine function has its maximum value 1=>(1/2)sin2X has max value=1/2. Originally Answered: What is the minimum value of sinx cosx?

Which of the following is the minimum real value of 2 sin squared theta 2 cos squared theta?

So minimum value of √2sin(2xmethod(mwy is -√2. Hence minimum value of your question is -2√2.

What is the minimum value of 2 to the power sin x 2 to the power COSX?

Hence option (1) is the answer.

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What is the maximum and minimum value of sin theta cos theta?

Properties Of The Sine Graph sin θ = 0 when θ = 0 ˚ , 180˚ , 360˚ . Maximum value of sin θ is 1 when θ = 90 ˚. Minimum value of sin θ is –1 when θ = 270 ˚.

What is the minimum value of 2sin 2x 3cos 2x?

The minimum value will be obtained when cos2θ = 0. Therefore, the least value of 2 sin2θ + 3 cos2θ is 2.

What is the value of 2sin Cos?

Derivation of 2 Sin a Cos a Formula Hence, we have proved that 2 sin a cos a is equal to sin 2a.

What is minimum value of sin x?

−1
The minimum value of sinx is −1. At x = 270°, sinx = −1.

What is the value of 2 sin x cos x?

the
Therefore, the period of 2 sin x cos x is π.

What is the minimum value of 3cosx 4sinx 5?

0
Therefore, the minimum value of 3 cos x + 4 sin x + 5 is 0.

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What is the minimum and maximum value of sin sin x?

Minimum and maximum value of Sin Sin x is. Do not exist-1, 1; Sin -1 , Sin +1 – Sin 1 , Sin 1; We know that, -1 ≤ Sin nx ≤ 1 = Sin (-1) ≤ Sin x ≤ Sin (1) = – Sin 1 ≤ Sin x ≤ Sin 1 ; [Sin(-θ) is same as – Sin θ ] Therefore, Minimum value is –Sin 1 and maximum is Sin 1 ( correct answer D) The key to success is Practice!

What is the maximum value of Cos(x/2)?

For a cosine function the minimum value is -1 and maximum value is 1. -1 ≤ cos (x/2) ≤ 1 Multiply it by 3 -3 ≤ 3cos (x/2) ≤ 3

What is the value of sin 2 θ + cos2 θ?

We know that sin 2 θ + cos 2 θ = 1 (identitiy#1) (sin2 θ + cos2 θ) + sec 2 θ + cosec 2 θ + tan 2 θ + cot 2 θ = (1) + sec 2 θ + cosec 2 θ + tan 2 θ + cot 2 θ Using A.M ≥ G.M logic for tan 2 θ + cot 2 θ we get , = 1 + 2 + sec 2 θ + cosec 2 θ

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What is the minimum value of √2sin(2x method)?

But the minimum value is still same I.e. -√2. Again minimum value of sin (2x+pi/4) is -1. So minimum value of √2sin (2xmethod (mwy is -√2. Hence minimum value of your question is -2√2. I will suggest you to do it by basic method (method1) also so that you can get more feeling of it.