What is the moment of inertia of a hollow sphere about its tangent?

What is the moment of inertia of a hollow sphere about its tangent?

The moment of inertia of a hollow sphere about a tangent is 5/3MR2 WHERE M is mass and R is the radius of the sphere .

What is the moment of inertia of a hollow sphere about an axis passing through its centre?

The moment of inertia of a sphere of mass M and radius R about an axis passing through its centre is 52MR2.

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How do you find the moment of inertia of a hollow sphere?

Suppose the mass of a hollow sphere is M, ρ is the density, inner radius R2​ and outer radius R1​.

  1. ∴M=34​π(R13​−R23​)ρ
  2. I=52​(M1​R12​−M2​R22​)
  3. ∴I=52​×34​πρ(R15​−R25​)

What is the moment of inertia of a hollow cylinder?

The moment of inertia of hollow cylinder of mass M and radius R about its axis of rotation is MR2.

What is the moment of inertia of a hollow sphere and a solid sphere?

For a solid sphere I = 2/5*M*a^2. If density = d (can’t see how to type rho!) M= 4/3*pi*a^3*d so I = 8/15*pi*a^5*d. If the inside hollow has radius r, it has I = 8/15*pi*r^5*d.

What is the moment of inertia of a ring about a tangent to the periphery of the ring?

We know that, moment of inertia of a ring about its diameter is MR²/2. Hence, the moment of inertia of a ring about a tangent in the plane of the circle of the ring is 3MR²/2.

What is the moment of inertia for a solid sphere WRT a tangent touching to its surface?

32​MR2.

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What is moment of inertia of a sphere *?

Moment Of Inertia Of Sphere Moment of inertia of sphere is normally expressed as; I = (⅖ )MR2. Here, R and M are the radius and mass of the sphere respectively. Students have to keep in mind that we are talking about the moment of inertia of a solid sphere about its central axis above.

What is the moment of inertia of a ring about a tangent parallel to the plane of the ring M is the mass of the ring R the radius of the ring?

Let, the tangent be represented by XY and diameter be represented by AB. Therefore, the moment of inertia of ring about tangent in the plane of the ring is 3/2 MR2.

What is the moment of inertia of ring?

The moment of inertia of a circular ring about an axis perpendicular to its plane passing through its centre is equal to $M{{R}^{2}}$, where M is the mass of the ring and R is the radius of the ring. Hence, $I=M{{R}^{2}}$.

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