What is the value of I and J in the below code?

Discussion Forum

Que.	What is the final value of j in the below code? #include int main() { int i = 0, j = 0; if (i && (j = i + 10)) //do something ; }
b.	10
c.	Depends on the compiler
d.	Depends on language standard
	Answer:0

What is the difference between i ++ and ++ i in C?

The only difference is the order of operations between the increment of the variable and the value the operator returns. So basically ++i returns the value after it is incremented, while i++ return the value before it is incremented. At the end, in both cases the i will have its value incremented.

What is the value of N after the following code is executed?

n will be 4 after execution of the code. First n = x + c is executed ⇒ n = 2 + (-1) = 1. Next, n = n – c + x is executed. So final value of n is 4.

What will I and J equal after the code below is executed?

What will i and j equal after the code below is executed? Explain your answer. int i = 5; int j = i++; After the above code executes, i will equal 6, but j will equal 5.

What is the value of i and j After executing the following lines?

Explanation : comma operator is executed from left to right so until j<20 for loop statement is true, so both i and j are incremented. So, i = 20 and j = 20.

What is I and J in C programming?

It is a variable that contains the address of other variable ( i in this case). Since j is a variable the compiler must provide it space in the memory. As you can see, i’s value is 3 and j’s value is i’s address. But wait, we can’t use j in a program without declaring it.

What will happen when the below code snippet is executed?

What will happen when the below code snippet is executed? Explanation: Every function call is stored in the stack memory. So, my_recursive_function() will be called continuously till the stack overflows and there is no more space to store the function calls. At this point of time, the program will stop abruptly.

What is the value of i after the following code snippet executes int i 8 i >> 2?

Question: What is the value of i after the following code snippet executes? int i = 8; i >>=2; Answer: i is 2.

What will be the output of the following code * 1 point Captionless image?

The output of the given code is “Hii”.

What is the value of i after the?

After the loop exists, the value of i must be zero, and that is what is printed. However, the starting value of i is 1. That it happens to print 0 is just a fluke, because your program invokes undefined behaviour: Each iteration you increment it by 1.

What does == mean in C programming?

== is an Equal To Operator in C and C++ only, It is Binary Operator which operates on two operands. == compares value of left and side expressions, return 1 if they are equal other will it will return 0.