What is the value of m and N in this equation?

(x + m) (x + n) = x 2 + 5x + mn and x ≠ 0. The numbers m and n are integers. As we have no other information about the values of m and n from the question stem, let us analyse the individual statements.

What is the sum of consecutive positive integers n1 to N2?

The sum of consecutive positive integers from n 1 to n 2 is equal to: n 1 + (n 1 + 1) + + n 2 = n 2(n 2 + 1) / 2 – n 1(n 1 – 1) / 2.

What is the sum of positive integers?

The Sum of Positive Integers Calculator is used to calculate the sum of first n numbers or the sum of consecutive positive integers from n 1 to n 2 . The sum of the first n numbers is equal to:

Which statement is not sufficient to determine the value of M+N?

As we can determine the value of m + n, statement 1 is sufficient to answer the question. However, from this statement we cannot determine either the individual values of m and n or their sum. Hence, statement 2 is not sufficient to answer the question. Since we can determine the answer from statement 1 individually, this step is not required.

Is the integer m^2 always odd?

There exists therefore an integer M such that : n (n+1) is always dividible by 2 (it’s for instance 2 times our S from the beginning, but here is a more trivial reason, among to consecutive integers, one must be even) and therefore M^2 is odd, implying that M must be odd.

How to find the sum of consecutive integers summing to N?

We can use dynamic programming to calculate the sums of 1+2+3+…+K for all K up to N. sum [i] below represents the sum 1+2+3+…+i. With these sums we can quickly find all sequences of consecutive integers summing to N. The sum i+ (i+1)+ (i+2)+…j is equal to sum [j] – sum [i] + 1. If the sum is less than N, we increment j.

How many distinct integers does 1/M+1/n have?

Conclusion: There are two distinct integers m and n, namely m=1 and n=-1, such that 1/m+1/n is an integer. Know someone who can answer?