What is the velocity of a projectile at its maximum height when it is thrown straight up?

When a projectile reaches maximum height, the vertical component of its velocity is momentarily zero (vy = 0 m/s).

How much time does the projectile take to reach the maximum height?

It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance). You have 176 seconds, or 2 minutes and 56 seconds, until the cannonball destroys the cannon that fired it.

When velocity of projectile is maximum?

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

When a projectile reaches its maximum speed what is its vertical velocity?

At its highest point, the vertical velocity is zero.

What happens to a projectile when it reaches its maximum height?

When the projectile reaches the maximum height, it stops moving up and starts falling. It means that its vertical velocity component changes from positive to negative – in other words, it is equal to 0 for a brief moment at time t (Vy=0). If Vy – g * t (Vy=0) = 0, then we can reformulate this equation to t (Vy=0) = Vy / g.

How do you find the vertical distance of a projectile?

1 When the projectile reaches the maximum height, it stops moving up and starts falling. 2 If Vy – g * t (Vy=0) = 0, then we can reformulate this equation to t (Vy=0) = Vy / g. 3 Now, we simply find the vertical distance from the ground at that time: hmax = Vy * t (vy=0) – g * (t (Vy=0))² / 2 = Vy² / (2

What is the time interval between the projectile passing the point?

The time interval between the projectile passing the point and being at maximum height is the same, \\ (\\Delta t\\). magnitude of velocity: the magnitude of the velocity at the same point on the upward and downward motion will be the same, the direction will be reversed, as indicated by the shaded region in Figure 3.2 .

What is the horizontal and vertical velocity component of projectile motion?

The horizontal velocity component Vx is equal to V * cos(α). The vertical velocity component Vy is equal to V * sin(α). Three vectors – V, Vx and Vy – form a right triangle. If the vertical velocity component is equal to 0, then it’s the case of horizontal projectile motion.