What is the velocity of the ball when it returns to the ground?

Conclusion: The magnitude of the velocity of the ball is 26.3 m/s for the parabolic motion just before it hits the ground and this greater than the 17.1 m/s for the velocity of the ball that falls straight downward.

When a ball is thrown vertically upwards with velocity v?

When a ball is thrown vertically upwards with velocity v0, it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity.

What is the initial velocity of the ball thrown vertically upwards?

A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (1) The maximum height to which it rises. (2) The total time it takes to return to the surface of the earth. Initial velocity of the ball (u) = 49m/s.

How do you find the acceleration of a thrown ball?

Use the formula v = u -gt. This is the first equation of motion and can be derived easily. u = velocity with which the ball was thrown or the initial velocity. g = acceleration due to gravity. I am taking it as 10m/s^2 in the downward direction . So it will be -10. t is obviously time. Putting the values , v= 40 -10.6 = -20m/s.

What is the final velocity after time t for upward motion?

Velocity after time t for upward motion is v=u-gt. Velocity v will be zero after 40/9.8 or 200/49 seconds. After that time the ball will start falling down and the velocity after 6 seconds when the ball was thrown up will be 9.8* (6–200/49) which comes out to be 18.8 m/s. This final velocity will be downwards.

How high would the ball reach if the initial speed becomes 2U?

So, the ball will go 81.632 metres high. If a ball thrown vertically upwards with initial speed of “u” reached “h” meters, how high would the ball reach if the initial speed becomes 2u (in terms of h)? If you want quick answer then it is 2h in terms of 2u.