What number of moles will be produced from 64g of O2?

64 gram oxygen = 64/16 = 4 mole oxygen.

How much water will be formed when 32 grams of hydrogen and 32 grams of oxygen are mixed and allowed to react?

32g O2 x 36.03056g H20/31.9988g O2 this way the O2 cancels out and you are left with just the H2O so your raw answer would be 36.0319112, then if your instructor requires a significant figure answer that would be to 2 significant figures the information you were given 32g O2, so as above 36g or Water are produced.

How much water is produced of 10.00 grams of hydrogen react with 10.00 grams of oxygen?

How much water can be produced when 10 grams of H2 is made to react with an amount of oxygen? There are 180 grams or 10 mol of H2O produced.

How many grams of H2O are produced when 2.50 moles of oxygen are used?

Thus, when 2.5 mol of oxygen reacted with hydrogen, 2 * 2.5 mol = 5 mol of water is produced. The molar mass of water is 18 g/mol. One mol of water weighs 18 g. 5 mol of water weights 5 * 18 = 90 g.

How many molecules are in 64 grams of o2?

so,your answer is 12.04×10^23 molecules.

How many atoms are present in 64 amu of oxygen?

Answer: There are 4 atoms present in 64 amu of oxygen. Explanation: We know that, one oxygen atom has atomic mass 16 u.

What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen in moles?

The molecular masses of hydrogen, oxygen and water are 2 g/mole, 32 g/mole and 18 g/mole respectively. 2×2=4 g of hydrogen reacts with 1×32=32 g of oxygen to form 2×18=36 g of water. =9 g of water. 9 grams of water can be produced when 8 g of hydrogen reacts with 8 g oxygen.

How many moles of water are produced when 8 moles of oxygen completely react with hydrogen?

So for every mole of H2 you will form a mole of water, assuming you have sufficient oxygen to react with it all. The atomic weight of hydrogen atoms is 1, but the molar mass of diatomic H2 is 2 g/mol. Therefore, 8 g of H2 is 4 moles. Therefore you will form 4 moles of water.

How many moles of water are produced when 3.0 moles of oxygen react?

AS given, one mole of water is formed from a half mole quantity of dioxygen gas. Here, 3.00⋅mol of H2O are produced, and NECESSARILY, HALF an EQUIV of dioxygen gas are required… i.e. 1.5⋅mol with respect to O2 , a mass of 48⋅g .

How many moles of water will be produced when 8.0 grams of hydrogen gas react with the oxygen in the air?

Therefore, 8 g of H2 is 4 moles. Therefore you will form 4 moles of water.

How many grams of H2O are there in 2.50 mol of H2O?

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2O, or 18.01528 grams.

How many grams of oxygen are required to produce 358.5 grams zno?

And we have 358.5⋅g81.41⋅g⋅mol−1=4.40⋅mol of zinc oxide.

How many moles of water can be produced from two reactants?

Multiply the moles of each reactant by the mole ratio between each reactant and H2O from the balanced equation, so that the moles of reactant cancel, leaving H2O. The limiting reactant is O2, because it forms less H2O than H2. So the number of moles of water that can be produced is 196 mol H2O.

How do you calculate the amount of water produced from reactants?

Calculate the amount of water that is possible to be produced from each reactant. Multiply the moles of each reactant by the mole ratio between each reactant and H2O from the balanced equation, so that the moles of reactant cancel, leaving H2O. The limiting reactant is O2, because it forms less H2O than H2.

What would happen if the number of moles of cao2h2 was doubled?

What would happen to the amount of H2O produced in the reaction if the number (amount) of moles of Ca O2H2 were doubled but the number of moles of JF were kept the same? Nothing would happen. State Gay-Lussac’s Law and its limitations.

How many grams of NH3 are formed when N2 reacts with H2?

1 gram of N2 reacts with 3 grams of H2 to make 2 grams of NH3 Rewrite this statement to correct it. grams should be moles: 1 mole of N2 reacts with 3 moles of H2 to make 2 moles of NH3 Consider the following reaction: Fe2O3 (s) + 3CO (g) –> 2Fe (s) + 3CO2 (g)