Table of Contents
- 1 What speed should a body be thrown upward so that the distance Travelled in 5th and 6th second are equal?
- 2 What speed should a body with thrown upward so that the distance transferred in 5th S and S are equal?
- 3 At what speed a ball must be projected vertically upward so that distance Travelled by it in 5th second is equal to distance Travelled in sixth second in M’s ):-?
- 4 At what speed a ball must be projected vertically upward so that distance Travelled by it in 5th second is equal to distance Travelled in sixth second?
What speed should a body be thrown upward so that the distance Travelled in 5th and 6th second are equal?
5. 84 m/s.
What speed should a body with thrown upward so that the distance transferred in 5th S and S are equal?
Therefore, to traverse the same distance in 5th second and 6th second, the body should be thrown upwards with an initial velocity of 50 m/s.
What is the distance Travelled by a body thrown upward with a speed of 20m S?
Answer: What is the distance travelled by a body thrown upwards with a speed of 20m/s, under the effect of gravity in the first second of its motion? Is there a simple privacy law that actually makes sense? => Distance covered in 1st second of motion is 15.1 m .
What will be velocity at the maximum height when the body is thrown upwards?
zero
So at the maximum height, the kinetic energy of the body will be zero. i.e., at hmax, K=12mv2=0, where m is the mass of the body and v is the final velocity of the body. So at the maximum height, the velocity of the body is zero.
At what speed a ball must be projected vertically upward so that distance Travelled by it in 5th second is equal to distance Travelled in sixth second in M’s ):-?
49
At what speed a ball must be projected vertically upward so that distance travelled by it in 5th second is equal to distance travelled in sixth second (in m/s):- Correct answer is ’49’.
At what speed a ball must be projected vertically upward so that distance Travelled by it in 5th second is equal to distance Travelled in sixth second?
What is the distance Travelled by a body thrown upward?
From Newton’s first equation of motion, we know that, ⇒v=u−gt=0 as the object has zero velocity at time t at maximum height. Since, g≈10m/s2 , therefore, d≈5m , which means that if a body is thrown upwards, the distance covered by it in the last second of upward motion is about 5m irrespective of its initial speed.
When a body is thrown upwards with a force work done?
the displacement of the body is in an upward direction. Since the angle between the force and displacement is 180 degrees, the work done by the gravitational force on the body is negative.