Table of Contents
- 1 When two dice are tossed what is the probability of getting a doublet?
- 2 What is a doublet of even number?
- 3 When two dice are tossed what is the probability that the total score is a prime number?
- 4 What is the probability of having prime number on each dice?
- 5 What is the probability of getting an even sum?
When two dice are tossed what is the probability of getting a doublet?
Probability of getting a doublet = 6/36 = 1/6.
What is the probability of getting a doublet of odd numbers?
1/12 would be the probability of occurring a doublet of odd numbers when two dices are thrown together. Thus, 1/12 is the correct answer.
What is a doublet of even number?
Ruturaj answered this. It means that there are 2 same number of even numbers Like (2,2) , (4,4) , (6,6) 6.
When two dice are thrown what is the probability of getting a sum of 10?
When you consider the sum being 10, there are only 3 combinations. So, the probability of getting a 10 would be 3/36 = 1/12.
When two dice are tossed what is the probability that the total score is a prime number?
5/12
When two dice are thrown, the total number of sample spaces is 36. Hence, the probability of getting a sum of prime numbers = 15/36 = 5/12.
What is doublet of prime numbers?
As, we know that, The outcomes (1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6) are called doublets. So, → Prime Numbers doublets are = (2, 2), (3, 3) and (5, 5) = 3 Total . Therefore, → Probability of getting Prime Numbers doublet is = (Favorable outcomes) / (Total outcomes) = (3/36) = (1/12) (Ans.)
What is the probability of having prime number on each dice?
Hence, the probability of getting a prime number is 12.
When rolling two dice What is the probability that the sum of the dice is an even number?
First, the probability of rolling an even number: You can either have an odd number on each die, or an even number on each die. There is a 1/2 probability of rolling either an odd or even number, so both probabilities are 1/2 x 1/2 + 1/4, and adding those together gives a 1/2 probability of rolling any even number.
What is the probability of getting an even sum?
Thus, we have P(even sum)=1/2(P(first was even)+P(first was odd))=1/2(1)=1/2.