Which is the correct set of 4 quantum numbers?

There are four quantum numbers: principal quantum number, azimuthal quantum number, magnetic quantum number, and spin quantum number which tells the shape, size, and orientation of the orbital in the space. (n) represents the principal quantum number and it tells the shell number of the orbital.

What is the correct set of four quantum numbers for the valence electron of rubidium atom?

n=5,l=0,m=0,s=+12.

Which is the correct set of four quantum numbers for valence electron of rubidium Z 37?

The correct set of four quantum numbers for the valence (outermost) electron of rubidium (Z=37) is: 5,0,0,+12.

Which is the correct set of all four quantum number for Valonce electron of Na?

n=3,l=0,m=0,s=+21​

How do you find the set of quantum numbers for an element?

Look at the Periodic Table of Elements and find the element that you want to know the quantum number for. Find the principal number, which denotes the element’s energy, by looking in which period the element is found. For example, sodium is in the third period of the table, so its principal quantum number is 3.

What is the set of quantum numbers for last electron of K 19?

Write the values of all the four quantum numbers for the last electron in case of K (Z=19). The last electron is 4s1 and the different quantum numbers are : n=2,l=0,m=0,s=+1/2.

What is the set of quantum numbers for rubidium?

So, the quantum numbers are n=5,l=0; (for s-orbital) m=0 $(\because m = + l\,to\, – l)$ , s=$ + \dfrac{1}{2}$ or $ – \dfrac{1}{2}$ . Rubidium is a chemical element with atomic number 37 which means there are 37 protons and 37 electrons in the atomic structure.

How do you find the correct set of quantum numbers?

The valence electron resides in one of the 3p orbital. Hence the correct set of quantum numbers is: n=3, l=1, m=+1 or 0 or -1, s=+½ or -½. Conclusion: The correct set of quantum numbers among the given options is: 3, 1, -1, +½ i.e correct option is 3.

What is the set of four quantum numbers for N 4?

Table of Allowed Quantum Numbers

n	l	Orbital Name
4	0	4s
	1	4p
	2	4d
	3	4f

What sets of quantum numbers are possible for a 4d orbital?

For a 4d orbital, the value of n (principal quantum number) will always be 4 and the value of l (azimuthal quantum number) will always be equal to 2. The values of the magnetic quantum number range from -l to l, so the possible values of ml for the 4d orbital are -2, -1, 0, 1, and 2.

What is the set of quantum numbers for nitrogen?

Nitrogen – seven electrons

n	ℓ	ms
1	0	-½
2	0	+½
2	0	-½
2	1	+½

What are the quantum numbers for the valence (outermost) electron of rubidium (Z37)?

Correct set of four quantum numbers for the valence (outermost) electron of Rubidium (Z=37) is : Spin quantum number, s = +½ or -½ (there is only one electron and it can have clockwise or anticlockwise spins) Conclusion: The correct set of quantum numbers will be: 5, 0, 0, +½ or -½. Therefore correct option is 1.

What is the correct set of four quantum numbers for RB(Z = 37)?

Illustration 1: What is the correct set of four quantum numbers for the valence electron of rubidium (Z = 37)? Solution: The electronic configuration of Rb (Z = 37) is = 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 1 Magnetic quantum number, m = 0 (since for l = 0, there is only one value for m, that is 0)

What is the set of four quantum numbers for the valence electron?

Correct set of four quantum numbers for the valence (outermost) electron of Rubidium (Z=37) is : (IIT JEE 1986) 1) 5, 0, 0, +½.

What is the electron configuration of RB with Z37?

Correct set of four quantum numbers for the valence (outermost) electron of Rubidium (Z=37) is : Electronic configuration of Rb = 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 1 Check that there are 37 electrons.