Table of Contents

- 1 How many tiles whose length and breadth are 12cm and 5cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively?
- 2 How many tiles of measures 10cm 10cm are required to cover a surface of 4m 2.5 m?
- 3 How many tiles whose length and breadth are 12 and 5?
- 4 How many tiles with length 6 cm and Breadth 10 cm will be needed to fit in a region whose length is 120 cm and breadth is 50 cm?
- 5 How many tiles with dimensions 5 cm and 12 cm will be needed to fit a region whose length and breadth 70cm and 36 cm are respectively?
- 6 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit?
- 7 How do you calculate the number of tiles on a floor?
- 8 How many tiles do I need to cover a 3m floor?

## How many tiles whose length and breadth are 12cm and 5cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively?

42 tiles

Summary: It is given that the tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are given. We found that 240 tiles are required in the 1st case and 42 tiles are required in the 2nd case.

## How many tiles of measures 10cm 10cm are required to cover a surface of 4m 2.5 m?

no. of tiles required=1000.

**How many square tiles of side 12 cm will be needed to fit in a rectangular region whose length and breadth are 150 cm and 96 cm respectively?**

Thus, 240 tiles are required.

**How many tiles of length 10cm and breadth 6cm respectively will be required to fit in a rectangular floor whose length and breadth are 4m and 300cm respectively?**

ANswer : ✦2000 tiles should be required to fit a rectangular floor.

### How many tiles whose length and breadth are 12 and 5?

Hence, 42 tiles are required.

### How many tiles with length 6 cm and Breadth 10 cm will be needed to fit in a region whose length is 120 cm and breadth is 50 cm?

Answer: (1) = 120*50/6*10 = 50 tiles . (2) = 90*40/6*10 = 60 tiles . (3) = 120*120/6*10 = 240 tiles .

**How many tiles whose length and breadth are 10cm and 6cm respectively?**

Mensuration | Exercise 10.3 Thus, 42 tiles are required.

**How many tiles whose length and breadth are 13 cm and 7 cm respectively?**

Answer : 800 tiles are required to cover the region.

## How many tiles with dimensions 5 cm and 12 cm will be needed to fit a region whose length and breadth 70cm and 36 cm are respectively?

## How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit?

**How many tiles whose length and breadth are 15 cm and 4 cm respectively will be needed to fit in a rectangular region whose length is 100 cm and breadth is 120 cm?**

**How many tiles will it take to cover 120000cm^2 of area?**

Given that length of floor is 4m and breadth is 3m, we get area of total floor as 12m^2 or 120000cm^2. Now, assuming the tiles are square in shape and with a side of 20cm each, the area that would be covered by the tile would be 20×20 = 400cm^2. So, to cover 120000cm^2 of area we need 120000/400 number of tiles.

### How do you calculate the number of tiles on a floor?

Knowing these, our online tile calculator can calculate the area size and the area of a single tile. From there, the basic formula to calculate the number of tiles required to cover an area is to divide the size of the area by the area of a single tile: Number of tiles = area size / single tile area.

### How many tiles do I need to cover a 3m floor?

Well each metre would require five 20 x 20 cm tiles laid side-by-side. So for the length of 4m, you would need 20 (4 x 5) tiles across and for the breadth of 3 m, you would need 15 (3 x 5) tiles across. So in total you would need 20 x 15 = 300 tiles to cover the floor.

**How many tiles do I need for a skirting board?**

This means you will need 2.5 (100/40) tiles per running metre of your room perimeter. You room perimeter is 14 m (4+4+3+3). This will mean you will need 35 (14 x 2.5) additional tiles for skirting. Laying pattern: The above calculation is based on the orthogonal laying pattern (the tile edges match and run parallel to walls).